Is array[0] vs. array[] { } the same?
Today I was writing some code, where I needed create initially empty array. I wondered if the array[0] vs. array[] { } is the same. Alike with the string concatenation.
Without writing further text. Lines:
private static void Test1()
{
string[] s1 = new string[0];
Console.WriteLine(s1);
}
private static void Test2()
{
string[] s2 = new string[] { };
Console.WriteLine(s2);
}
resulted in this IL:
.method private hidebysig static void Test1() cil managed
{
// Code size 14 (0xe)
.maxstack 1
.locals init ([0] string[] s1)
IL_0000: ldc.i4.0
IL_0001: newarr [mscorlib]System.String
IL_0006: stloc.0
IL_0007: ldloc.0
IL_0008: call void [mscorlib]System.Console::WriteLine(object)
IL_000d: ret
} // end of method Program::Test1
.method private hidebysig static void Test2() cil managed
{
// Code size 14 (0xe)
.maxstack 1
.locals init ([0] string[] s2)
IL_0000: ldc.i4.0
IL_0001: newarr [mscorlib]System.String
IL_0006: stloc.0
IL_0007: ldloc.0
IL_0008: call void [mscorlib]System.Console::WriteLine(object)
IL_000d: ret
} // end of method Program::Test2
As you (and I) can see, the code is the same (I was kind of expecting that – but what’s better proof than IL?). So you don’t need to worry using the first or the other syntax.
